Top-25 Thumb rules for steam Turbine
Top-25 Thumb rules for steam Turbine

Top-36 Thumb rules for steam Turbine

For example: 20 MW turbine needs lube oil pump of capacity = 2 X 20 = 40 M3/Hr

For example, 20 MW Turbine needs a Control oil pump of capacity = 40 M3/hr X 10% = 4 M3/Hr.

For example, 20 MW Turbine needs a MOT of storage capacity = 225 X (40 + 4) = 9900 M3 or Litres

For example, 20 MW Turbine needs a Over head tank of storage capacity = 9900 X 35% = 3465 = 3500 appx.Litres

For example, 20 MW Turbine needs a emergency oil pump of capacity = 40 M3/hr X 30% = 12 M3/Hr.

For example, 20 MW Turbine needs a oil cooler of heat load = 40 M3/hr X 10 = 400 KW.

For example, 20 MW Turbine needs a oil cooler of heating surface = 400 KW X 20% = 80 M2

For example, Lube oil flow to 20 MW Turbine bearings = 40 M3/Hr X 25% = 10 M3/Hr

For example, Lube oil flow to 20 MW Turbine bearings = 40 M3/Hr X 65% = 26 M3/Hr

For example, Lube oil flow to 20 MW Turbine bearings = 40 M3/Hr X 10% = 4 M3/Hr

For example, A reciprocating air compressor of FAD 8.75 M3/min and Discharge pressure 8 Kg/cm2 will consume power = 8.75 X 8 = 70 KW

For example, A screw air compressor of FAD 8.75 M3/min and Discharge pressure 8 Kg/cm2 will consume power = 8.75 X 8 / 1.5 = 47 KW (appx)

For example, Cooling water required for a reciprocating air compressor of FAD 8.75 M3/min and Discharge pressure 8 Kg/cm2 will consume po = 8.75 X 140% = 12.25 M3/hr

For example, a 20 MW power plant needs instrument compressor of capacity = 20/4 = 5 M3/min (1-working + 1-Standby)

For example, a 20 MW power plant needs instrument compressor of capacity = 20/4.2 = 4.76 M3/min (1-working + 1-Standby)

And, minimum exhaust steam flow to condenser is Inlet steam flow X 10%

And, Maximum exhaust steam flow to condenser is Inlet steam flow X 70%

For example, a 20 MW steam Turbine will have Oil Vapour extraction fan of capacity = (40 M3/Hr+4 M3/Hr) X 9 =396 M3/sec

For, example, as a Thumb rule a 20 MW Turbine of maximum exhaust of 80 TPH, needs circulating cooling water through surface condenser = 80 X 70 = 5600 M3/Hr

For example, a 20 MW Power plant needs total auxiliary cooling water for Generator air cooler, oil cooler, Boiler feed pump, air compressors etc = 5600 X 8% = 448 M3/Hr, 450 M3/Hr appx

So, Total circulating cooling water = MCW + ACW = 5600 + 450 = 6050 M3/Hr

For example, A 20 MW power plantโ€™s cooling tower capacity for total cooling water circulating flow is; 6050 X 25% =1513 M3, 1500 M3 (Appx)

Example: Turbine operating at 67 kg/cm2 pressure, its inlet steam temperature should be285+50 =335 deg C

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